kak tolong di bantu cari jawabannya plisssss kak baik tolong di bantu
Dik:
PQ = 30 cm
∠OPQ = 45°
∠POQ = 60°
Dit: OQ?
Jawab:
Gunakan aturan sinus
[tex]\frac{sinP}{sinO} =\frac{OQ}{PQ}[/tex]
[tex]\frac{sin45}{sin60} =\frac{OQ}{30cm}[/tex]
[tex]\frac{\frac{1}{2}\sqrt{2} }{\frac{1}{2}\sqrt{3} } =\frac{OQ}{30 cm}[/tex]
√3 OQ = 30√2 cm
OQ = [tex]\frac{30\sqrt{2} }{\sqrt{3} }[/tex] cm (dikali [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] )
OQ = [tex]\frac{30\sqrt{6} }{3}[/tex] cm
OQ = 10√6 cm
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