MATERI EKSPONEN
[tex] {3}^{ - 1} + {2}^{ - 1} [/tex]
[tex] {5}^{ - 1 } - {5}^{0} [/tex]
[tex]( {2}^{ - 1} + {3}^{ - 1} ) {}^{ - 1} [/tex]
[tex]( {5}^{ - 1} - {2}^{ - 1} ) { \\ }^{ - 1} [/tex]
[tex]( {7}^{ - 1} + {5}^{ - 1} )[/tex]
[tex]( {a}^{ - 1 } + {b}^{ - 1} ) { \\ }^{0} [/tex]
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[tex] {3}^{ - 1} + {2}^{ - 1} [/tex]
[tex] {5}^{ - 1 } - {5}^{0} [/tex]
[tex]( {2}^{ - 1} + {3}^{ - 1} ) {}^{ - 1} [/tex]
[tex]( {5}^{ - 1} - {2}^{ - 1} ) { \\ }^{ - 1} [/tex]
[tex]( {7}^{ - 1} + {5}^{ - 1} )[/tex]
[tex]( {a}^{ - 1 } + {b}^{ - 1} ) { \\ }^{0} [/tex]
[tex] no1 \\ {3}^{ - 1} + {2}^{ - 1} \\ = \frac{1}{ {3}^{1} } + \frac{1}{ {2}^{1} } \\ = \frac{1}{3} + \frac{1}{2} \\ = \frac{(1 \times 2) + (1 \times 3)}{6} \\ = \frac{2 + 3}{6} \\ = \frac{5}{6} \\ \\ no2 \\ {5}^{ - 1} - {5}^{0} \\ = \frac{1}{ {5}^{1} } - 1 \\ = \frac{1}{5} - 1 \\ = \frac{(1 \times 1) - (1 \times 5)}{5} \\ = \frac{1 - 5}{5} \\ = \frac{ - 4}{5} \\ = - \frac{4}{5} [/tex]
catatan; bilangan berapapun dipangkatkan 0 hasilnya adalah 1
no 3 dst caranya sama seperti no 1&2 ya
misal 3^1 × 3^2 = 3^(1+2)
pangkatnya dijumlah
jika (3^1)^2 = 3^(1×2)
pangkatnya dikali
[answer.2.content]
